Question

(t^2-9t)^2+22(t^2-9t)+112=0

Answer 1

t2-9t=a

a2+22a+112=0

delta=121-112=9

a=-11+3=-8   a2=-11-3=-14

t2-9t=-8

t2-9t+8=0

D=81-32=49   t1=9+7/2=8    t2=9-7/2=1    

t2-9t=-14

t2-9t+14=0

D=81-56=25  t1=9+5/2=7  t2=9-5/2=2