Question

Решить неравенство:
log0,3 (x-4) < 0

Answer 1

$log_{0,3}(x-4)\ \textless \ 0\\OD3: x-4\ \textgreater \ 0,x\ \textgreater \ 4\\0\ \textless \ 0,3\ \textless \ 1\\\\log_{0,3}(x-4)\ \textless \ log_{0,3}1\\x-4\ \textgreater \ 1\\x\ \textgreater \ 1+4\\x\ \textgreater \ 5\\x\in(5;+\infty)$

Answer 2

log₀,₃(x-4)<0        ОДЗ: x>4
log₀,₃(x-4)<log₀,₃1
x-4>1
x>5   x∈(5;+∞).