Question

представьте в виде логарифма: 32^1/5=2; 3^-1=1/3; 27^2/3=9

Answer 1

32¹/⁵ =2
log₃₂ 2 =1/5

3⁻¹ =1/3
log₃ (1/3)=-1

27²/³ =9
log₂₇ 9=2/3

Answer 2

$32^{ \frac{1}{5}}=2 \\ log_{32}2= \frac{1}{5} \\ \\ 3^{-1}= \frac{1}{3} \\ log_{3}\frac{1}{3}=-1 \\ \\27^{ \frac{2}{3}}=9 \\ log_{27}9= \frac{2}{3}$