Question

ДОПОМОЖІТЬ БУДЬ ЛАСКА !!!!!!!!!!!!!!!!!

Answer 1

{3(x+8)≥4(7-x)
{(x+2)(x-5)≥(x+3)(x-4)

3(x+8)≥4(7-x)
3x+24≥28-4x
3x+4x≥28-24
7x≥4
x≥4/7

(x+2)(x-5)≥(x+3)(x-4)
x²+2x-5x-10≥x²+3x-4x-12
x²-3x-10≥x²-x-12
x²-x²-3x+x≥-12+10
-2x≥-2
x≤1
                  \\\\\\\\\\\\\\\\\\\\\\\\\\
--------- 4/7 --------------- 1 ---------------
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
x∈[4/7; 1]