Question

Ребя помогите решить очень срочно*)

Answer 1

sin28cos32+sin32cos28=sin(32+28)=sin60=√3/2
cos10π/19cos9π/19-sin10π/19sin9π/19=cos(10π/19+9π/19)=cosπ=-1
cos7π/8sin5π/8-sin7π/8cos5π/8)=sin(5π/8-7π/8)=sin(-π/4)=-√2/2
sin127sin37+cos127cos37=cos(127-37)=cos90=0