Question

решить пример 3x²+x-2≥0

Answer 1

$3x^2+x-2geq0\3x^2+x-2=0\x_{1,2}=frac{-1^+_-sqrt{25}}{6}=frac{-1^+_-5}{6}\x_1=frac{2}{3} x_2=-1\///(+)///[-1]...(-)...[frac{2}{3}]///(+)/// textgreater x\xin(-infty;-1]cup[frac{2}{3};+infty)$