Ответы
Ответ дал:
0
#2.
а)![frac{3x-1}{ x^{2} }+ frac{x-9}{3x}= frac{3(3x-1)}{3 x^{2} }+ frac{x(x-9)}{3 x^{2} }= frac{9x-3+ x^{2} -9x}{3 x^{2} }= frac{ x^{2} -3}{3 x^{2} } frac{3x-1}{ x^{2} }+ frac{x-9}{3x}= frac{3(3x-1)}{3 x^{2} }+ frac{x(x-9)}{3 x^{2} }= frac{9x-3+ x^{2} -9x}{3 x^{2} }= frac{ x^{2} -3}{3 x^{2} }](https://tex.z-dn.net/?f=+frac%7B3x-1%7D%7B+x%5E%7B2%7D+%7D%2B+frac%7Bx-9%7D%7B3x%7D%3D+frac%7B3%283x-1%29%7D%7B3+x%5E%7B2%7D+%7D%2B+frac%7Bx%28x-9%29%7D%7B3+x%5E%7B2%7D+%7D%3D+frac%7B9x-3%2B+x%5E%7B2%7D+-9x%7D%7B3+x%5E%7B2%7D+%7D%3D+frac%7B+x%5E%7B2%7D+-3%7D%7B3+x%5E%7B2%7D+%7D+)
б)![frac{1}{2a-b}- frac{1}{2a+b}= frac{2a+b-2a+b}{(2a-b)(2a+b)}= frac{2b}{4 a^{2} - b^{2} } frac{1}{2a-b}- frac{1}{2a+b}= frac{2a+b-2a+b}{(2a-b)(2a+b)}= frac{2b}{4 a^{2} - b^{2} }](https://tex.z-dn.net/?f=+frac%7B1%7D%7B2a-b%7D-+frac%7B1%7D%7B2a%2Bb%7D%3D+frac%7B2a%2Bb-2a%2Bb%7D%7B%282a-b%29%282a%2Bb%29%7D%3D+frac%7B2b%7D%7B4+a%5E%7B2%7D+-+b%5E%7B2%7D+%7D+)
в)![frac{5}{c+3}- frac{5c-2}{ c^{2}+3 }= frac{5c-5c+2}{ c(c+3)}= frac{2}{ c^{2} +3c} frac{5}{c+3}- frac{5c-2}{ c^{2}+3 }= frac{5c-5c+2}{ c(c+3)}= frac{2}{ c^{2} +3c}](https://tex.z-dn.net/?f=+frac%7B5%7D%7Bc%2B3%7D-+frac%7B5c-2%7D%7B+c%5E%7B2%7D%2B3+%7D%3D+frac%7B5c-5c%2B2%7D%7B+c%28c%2B3%29%7D%3D++frac%7B2%7D%7B+c%5E%7B2%7D+%2B3c%7D+)
#3.
![frac{2a}{a-5} - frac{5}{a+5}+ frac{ 2a^{2} }{25- a^{2} }= frac{2a}{a-5}- frac{5}{a+5} - frac{2 a^{2} }{ (a-5)(a+5)}= frac{2 a^{2}+10a-5a+25- 2a^{2} }{(a-5)(a+5)} = frac{2a}{a-5} - frac{5}{a+5}+ frac{ 2a^{2} }{25- a^{2} }= frac{2a}{a-5}- frac{5}{a+5} - frac{2 a^{2} }{ (a-5)(a+5)}= frac{2 a^{2}+10a-5a+25- 2a^{2} }{(a-5)(a+5)} =](https://tex.z-dn.net/?f=+frac%7B2a%7D%7Ba-5%7D+-+frac%7B5%7D%7Ba%2B5%7D%2B+frac%7B+2a%5E%7B2%7D+%7D%7B25-+a%5E%7B2%7D+%7D%3D+frac%7B2a%7D%7Ba-5%7D-+frac%7B5%7D%7Ba%2B5%7D+-+frac%7B2+a%5E%7B2%7D+%7D%7B+%28a-5%29%28a%2B5%29%7D%3D+frac%7B2+a%5E%7B2%7D%2B10a-5a%2B25-+2a%5E%7B2%7D++%7D%7B%28a-5%29%28a%2B5%29%7D+%3D+)
![frac{5a+25}{(a-5)(a+5)}= frac{5(a+5)}{(a-5)(a+5)}= frac{5}{a-5} frac{5a+25}{(a-5)(a+5)}= frac{5(a+5)}{(a-5)(a+5)}= frac{5}{a-5}](https://tex.z-dn.net/?f=+frac%7B5a%2B25%7D%7B%28a-5%29%28a%2B5%29%7D%3D+frac%7B5%28a%2B5%29%7D%7B%28a-5%29%28a%2B5%29%7D%3D+frac%7B5%7D%7Ba-5%7D+)
а)
б)
в)
#3.
Вас заинтересует
1 год назад
1 год назад
6 лет назад
6 лет назад
9 лет назад
9 лет назад
9 лет назад