Question

разложить на множители 2b-2c+ab--ac,ab-ac+5b-5c,xy-xz-y+z,km-k-2m+2,3x-3y-2ax+2ay

Answer 1

2b-2c+ab-ac= 2(b-c) + a(b-c) == (b-c)(2+a)ab-ac+5b-5c = a(b-c) + 5(b-c) ==(b-c)(a+5)

xy-xz-y+z = x(y-z) - (y-z) = (y-z)(x-1)

km-k-2m+2 = k(m-1) -2(m-1) ==(m-1)(k-2)3x-3y-2ax+2ay=x(3-2a) -y(3-2a) == (3-2a)(x-y)