Question

3cos2x=4-11cosx Помогите!!!!!

Answer 1

3(2cos^2x-1)-4+11cosx=0
6cos^2x+11cosx-7=0
cosx=t
6t^2+11t-7=0
D=289=17^2
t1=1/2
t2=-28/12=-7/3
cosx=-7/3 - не подходит
cosx=1/2
x=+-π/3+2πn, n ∈ z