Question

sin(п-п3)cos(n-п4)sin(п2+п6)

Answer 1

=sin(π/3) * (-cos(π/4))*cos(π/6)=
$= frac{ sqrt{3} }{2}*(- frac{ sqrt{2} }{2} )* frac{ sqrt{3} }{2}=- frac{3 sqrt{2} }{8}$