Question

log8(x)+logsqrt2(x)=14

Answer 1

$frac{log2(x)}{log2(8)} + frac{log2(x)}{log2(sqrt{2})} =14 log2(x)(frac{1}{3} +frac{1}{0,5)} =14 log2(x)(frac{1}{3} +2} =14 log2(x)(frac{7}{3} } =14 log2(x) =6 x=2^{6} x=64$" title="$frac{log2(x)}{log2(8)} + frac{log2(x)}{log2(sqrt{2})} =14 log2(x)(frac{1}{3} +frac{1}{0,5)} =14 log2(x)(frac{1}{3} +2} =14 log2(x)(frac{7}{3} } =14 log2(x) =6 x=2^{6} x=64$" alt="$frac{log2(x)}{log2(8)} + frac{log2(x)}{log2(sqrt{2})} =14 log2(x)(frac{1}{3} +frac{1}{0,5)} =14 log2(x)(frac{1}{3} +2} =14 log2(x)(frac{7}{3} } =14 log2(x) =6 x=2^{6} x=64$" />

 

 

после 14 везде с красной строки