Question

1×12-5÷1= 0×9+7×3= 39×1 +39÷39= 14÷1-6×1= 14+4×0= ( 14+4 ) ×0= найди значения выражения

Answer 1

1×12-5:1=7, 0×9+7×3=21, 39×1+39:39=40, 14:1-6×1=8, 14+4×0=14, (14+4)×0=0

Answer 2

1×12-5÷1= 0×9+7×3= 39×1 +39÷39= 14÷1-6×1= 14+4×0= ( 14+4 ) ×0= 0