Question

1)Cократите дробь 9a^2+6a+1
_________
6ax+2x-3a-1

2) 4b^2-12b
_______
b^2-9

Answer 1

$\frac{9a ^{2} +6a+1}{6ax+2x-3a-1} = \frac{(3a+1)^2}{2x(3a+1) -(3a+1)} = \frac{(3a+1)^2}{(3a+1)(2x-1)} = \frac{3a+1}{2x-1}$

$\frac{4b^2-12b}{b^2-9} = \frac{4b(b-3)}{(b-3)(b+3)} = \frac{4b}{b+3}$

Answer 2

9a²+6a+1              (3а+1)²                (3а+1)²                   (3а+1)²              3а+1 __________ =_________ =  _________________ = __________ =      ____
6ax+2x-3a-1     (6ах+2х)-(3а+1)     2х(3а+1)-(3а+1)   (3а+1)(2х-1)         2х-1
  

2) 4b²-12b    4b(b-3)       4b
  _______ =________ = ____
        b²-9      (b-3)(b+3)    b+3