Question

Найти корень уравнения 5^(x–7)=1/125, log6(x+4)=log6(6x-6),

Answer 1

5ˇ(x-7)=1/125
5ˇ(x-7)=1/5ˇ3
5ˇ(x-7)=5ˇ(-3)
x-7=-3
x=7-3
x=4

log6 (x+4)=log6 (6x-6)
x+4=6x-6
5x=10
x=2