Question

Решите систему уравнений {у2+2х=2
Х+у=1

Answer 1

$left { {{ y^{2}+2x =2} atop {x+y=1}} right. textgreater left { {{ y^{2}+2-2y=2(1) } atop {x=1-y}} right. 1) y^{2}-2y+2-2=0 y^{2}-2y=0 y(y-2)=0 y=0(1), y-2=0, y=2(2) 1left { {{y=0} atop {x=1-0}} right. textgreater left { {{y=0} atop {x=1}} right. 2 left { {{y=2} atop {x=1-2}} right. textgreater left { {{y=2} atop {x=-1}} right.$

Ответ:(1;0);(-1;2)