Question

Решите уравнение ........................

Answer 1

(3(2x+1)^2 +4(2x+5)^2) /(2x+5)^2*(2x+1)^2 =7/(2x+5)(2x+1)

(3(4x^2+4x+1)+4(4x^2+20x+25)) /(2x+5)^2*(2x+1)^2 =7/(2x+5)(2x+1)

(12x^2+12x+3+16x^2+80x+100)/(2x+5)^2*(2x+1)^2 =7/(2x+5)(2x+1)

(28x^2+92x+103)/(2x+5)^2*(2x+1)^2 -7/(2x+5)(2x+1) =0

(28x^2+92x+103 -7(2x+5)(2x+1)) /(2x+5)^2*(2x+1)^2 =0

28x^2+92x+103 -7(4x^2 + 12x+5) =0

28x^2+92x+103 -28x^2 -84x -35 =0

8x +68 =0

8x = -68

x = -68 : 8

x = -8.5