Question

3sin^2x+7sinx*cosx+3cos^x=0 помогите решить

Answer 1

$3sin2x+7sinxcosx+3cosx=6sinxcosx+7sinxcosx+3cosx=$
$=13sinxcosx+3cosx$
$cosx(13sinx+3)=0 \ cosx=0\x= pi/2+ pi n,$n∈Ζ
$sinx=-3/13 \x=(-1)^karcsin(-3/13)+pi k,$, k∈Ζ