Question

x^2+y^2+z^2-2x+4y-6z+5=0

Answer 1

$x^2+y^2+z^2-2x+4y-6z+5=0\\(x^2-2x)+(y^2+4y)+(z^2-6z)=-5\\(x-1)^2-1+(y+2)^2-4+(z-3)^2-9=-5\\(x-1)^2+(y+2)^2+(z-3)^2=9; ; - ; ; yravnenie; sferu\\R=3; ,; C(1,-2,3); -; centr$