Question

(x-2)(3x+4)-3(x+1)^2 при x=-5/8

Answer 1

$(x-2)(3x+4)-3(x+1)^2=3x^2+4x-6x-8-3x^2-6x-3$$=-8x-11$ 

при x=-5/8

$frac{-8*-5}{8}-11=5-11=-6$