Question

(√a+(b-√ab)/(√a+√b)):(a/(√ab+b)+b/(√ab-a)-(a+b)/√ab) Очень срочно!

Answer 1

1)√a +(b-√(ab))/(√a+√b)=(a+√(ab)+b-√(ab))/(√a+√b)=(a+b)/(√a+√b)
2)a/[√b(√a+√b)]+b/[√a(√b-√a)]-(a+b)/√(ab)=
=(a√(ab)-a²+b√(ab)+b²-ab+a²-b²+ab)/[√ab)(b-a)]=
=(a√(ab)+b√(ab))/[√ab)(b-a)]=√(ab)(a+b)/[√ab)(b-a)]=(a+b)/(b-a)
3)(a+b)/(√a+√b):(a+b)/(b-a)=(a+b)/(√a+√b)*(√b-√a)(√b+√a)/(a+b)=√b-√a