Question

Тригонометрия.Упростить
1+cosa/1-cosa*tg^2a/2-sin^2a

Answer 1

Т.к. tg²(α/2) = (1-cosα)/(1+cosα)? njulf
(1+cosα)/(1-cosα) × (1-cosα)/(1+cosα)-sin²α=1-sin²α=cos²α