Question

найти производную функции y=sin^6(4x^3-2)

Answer 1

$y=sin^6(4x^3-2)$ 

$y'=6sin^5(4x^3-2)*cos(4x^3-2)*12x^2=$ 

$=72x^2sin^5(4x^3-2)*cos(4x^3-2)$