Question

Решите уравнение:

x^3 - 3x^2 - 4x +12 =0

Answer 1

x^2 * (x-3) - 4 * (x-3) = 0 
(x-3) * (x^2 - 4) = 0 
x1 = 3 
x^2 - 4 = 0 
x2 = 2 
x3 = -2

Answer 2

x^3-3x^2-4x+12=0
(x-3)*(x-2)*(x+2)=0

(x-3)=0
x1=3
 

(x-2)=0
x2=2
 

(x+2)=0
x3=-2