Question

sin(pi/18-8x)＝1
помогите решить.срочно надо

Answer 1

Решение
Sin(π/18-8x)＝1
- sin(8x - π/18) = 1
sin(8x - π/18) = - 1
8x - π/18 = - π/2 + 2πk, k ∈ Z
8x = - π/2 + π/18 + 2πk, k ∈ Z
8x = - 8π/18 + 2πk, k ∈ Z
x = - π/18 + πk/4, k ∈ Z