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в последнем степень x^-8/13........................
Приложения:
![](https://st.uroker.com/files/4cc/4cc7dce1760b8a237fc4d0f8a204a1bb.jpg)
Ответ дал:
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Здесь подходи формула:
![f'(x)=( x^{n} )'=n* x^{n-1} f'(x)=( x^{n} )'=n* x^{n-1}](https://tex.z-dn.net/?f=f%27%28x%29%3D%28+x%5E%7Bn%7D+%29%27%3Dn%2A+x%5E%7Bn-1%7D+)
![y'=(15x-8x^2+3)'=(15x)'-(8x^2)'+3'=15-8*2*x^{2-1}= \ 15-16x y'=(15x-8x^2+3)'=(15x)'-(8x^2)'+3'=15-8*2*x^{2-1}= \ 15-16x](https://tex.z-dn.net/?f=y%27%3D%2815x-8x%5E2%2B3%29%27%3D%2815x%29%27-%288x%5E2%29%27%2B3%27%3D15-8%2A2%2Ax%5E%7B2-1%7D%3D+%5C+15-16x)
![y'=(10 x^{2} +20x-7)'=(10 x^{2} )'+(20x)'-7'=10*2*x ^{2-1}+20= \ 20x+20=20(x+1) y'=(10 x^{2} +20x-7)'=(10 x^{2} )'+(20x)'-7'=10*2*x ^{2-1}+20= \ 20x+20=20(x+1)](https://tex.z-dn.net/?f=y%27%3D%2810+x%5E%7B2%7D+%2B20x-7%29%27%3D%2810+x%5E%7B2%7D+%29%27%2B%2820x%29%27-7%27%3D10%2A2%2Ax+%5E%7B2-1%7D%2B20%3D+%5C+20x%2B20%3D20%28x%2B1%29+)
![y'=( sqrt[13]{x^5})'=(x^{ frac{5}{13} })'= frac{5}{13}*x^{ frac{5}{13}-1 }=frac{5}{13}*x^{- frac{8}{13} }=frac{5}{13 sqrt[13]{x^8} } y'=( sqrt[13]{x^5})'=(x^{ frac{5}{13} })'= frac{5}{13}*x^{ frac{5}{13}-1 }=frac{5}{13}*x^{- frac{8}{13} }=frac{5}{13 sqrt[13]{x^8} }](https://tex.z-dn.net/?f=y%27%3D%28+sqrt%5B13%5D%7Bx%5E5%7D%29%27%3D%28x%5E%7B+frac%7B5%7D%7B13%7D+%7D%29%27%3D+frac%7B5%7D%7B13%7D%2Ax%5E%7B+frac%7B5%7D%7B13%7D-1+%7D%3Dfrac%7B5%7D%7B13%7D%2Ax%5E%7B-+frac%7B8%7D%7B13%7D+%7D%3Dfrac%7B5%7D%7B13+sqrt%5B13%5D%7Bx%5E8%7D+%7D)
Приложения:
![](https://st.uroker.com/files/4cc/4cc7dce1760b8a237fc4d0f8a204a1bb.jpg)
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