Question

Помогите.. очень срочно

Answer 1

1. $frac{7 x^{3} }{7 x^{-3} } = 1$
2. log5(25) = 2
3. log12(16) + log12(9) = log12(144) = 2
4.1$5^{x-2} = 25 => x = 4$
4.2 $3^{x-4} = 0$
      $x-4 = 0 => x = 4$
4.3 $2^{x+2} + 2^{x} = 5$  x = 0

Answer 2

В 4.2 уравнение = 1 (3 в степени x-4 = 1)