Question

решите уравнение
1) (х+9)²-х(х+8)=1
2) (х-11)²=(х-7)(х-9)
3) (х-4)(х+4)-(х+6)²=-16
4) (1-3х)²-х(9х-2)=5

Answer 1

$(x+9)^2-x(x+8)=1 \ x^2+18x+81-x^2-8x=1 \ 10x+80=0 \ 10x=-80 \ x=-8 \ \(x-11)^2=(x-7)(x-9) \x^2-22x+121=x^2-7x-9x+63 \ -22x+16x=63-121 \ -6x=-58 \ x= frac{58}{6}=9 frac{4}{6}=9 frac{2}{3} \ \(x-4)(x+4)-(x+6)^2=-16 \ x^2-16-x^2-12x-36=-16 \ -12x-36=0 \ -12x=36 \ x=-3 \ \ (1-3x)^2-x(9x-2)=5 \ 1-6x+9x^2-9x^2+2x=5 \ -4x=4 \ x=-1$