Question

Решите пожалуйста!!!!! Очень надо!!!!!!!!!

Answer 1

(1+cos40°+cos2×40°)/(sin2×40°+sin40°)×ctg50°+2=(1+cos40°+2cos^2 40°-1)/(2sin40°cos40°+
sin40°)×ctg50°+2=
cos40°(1+2cos40°)/sin40°(2cos40°+1)×ctg50°+2=cos40°/sin40°×ctg50°+2=ctg40°ctg50°+2=
ctg(90°-50°)×ctg50°=tg50°×cth50°+2=
1+2=3.