Question

$sqrt2 x^{2} -5x+1=x-1$

Answer 1

$sqrt2 *x^2-5x=x-1\sqrt2*x^2-6x+1=0\D=36-4sqrt2\x_1=frac{6-sqrt{36-4sqrt2}}{2sqrt2}=frac{sqrt2(6-sqrt{36-4sqrt2})}{4}=frac{6sqrt2-sqrt{72-8sqrt2}}{4}\x_2=frac{6+sqrt{36-4sqrt2}}{2sqrt2}=frac{6sqrt2+sqrt{72-8sqrt2}}{4}$