Question

Решите уравнение
1) 3x^2-4x=0
2) x^3-x^2-x+1=0

Answer 1

1)
3x^2 - 4x = 0 
x (3x - 4) = 0 

x = 0 ;
3x - 4 = 0 => 3x = 4 => x = 4/3

Ответ 
0; 4/3

2)
x^3 - x^2 - x + 1 = 0 
x^2 (x - 1) - 1(x - 1) = 0 
(x - 1)(x^2 - 1) = 0 

x - 1 = 0 ==> x = 1;
x^2 - 1 = 0 => x^2 = 1 ==> x = ± 1

Ответ 
- 1; 1