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![x-1 textgreater 0\x textgreater 1 x-1 textgreater 0\x textgreater 1](https://tex.z-dn.net/?f=x-1+textgreater++0%5Cx+textgreater++1)
![log_{3} (x-1) leq 2 \log_{3} (x-1) leq 2log_{3}3\ log_{3} (x-1) leq log_{3}3^2\x-1 leq 9\x leq 10
log_{3} (x-1) leq 2 \log_{3} (x-1) leq 2log_{3}3\ log_{3} (x-1) leq log_{3}3^2\x-1 leq 9\x leq 10](https://tex.z-dn.net/?f=log_%7B3%7D+%28x-1%29+leq+2+%5Clog_%7B3%7D+%28x-1%29+leq+2log_%7B3%7D3%5C+log_%7B3%7D+%28x-1%29+leq+log_%7B3%7D3%5E2%5Cx-1+leq+9%5Cx+leq+10+%0A+)
Ответ:![1 textless x leq 10 1 textless x leq 10](https://tex.z-dn.net/?f=1++textless+++x++leq+10)
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![2-x textgreater 0\-x textgreater -2\x textless 2 2-x textgreater 0\-x textgreater -2\x textless 2](https://tex.z-dn.net/?f=2-x+textgreater++0%5C-x+textgreater++-2%5Cx+textless++2)
![log_{ frac{1}{5} } (2-x) textgreater -1\log_{ frac{1}{5} } (2-x) textgreater -1log_{ frac{1}{5} }frac{1}{5}\log_{ frac{1}{5} } (2-x) textgreater log_{ frac{1}{5} }5\2-x textless 5\-x textless 3\x textgreater -3 log_{ frac{1}{5} } (2-x) textgreater -1\log_{ frac{1}{5} } (2-x) textgreater -1log_{ frac{1}{5} }frac{1}{5}\log_{ frac{1}{5} } (2-x) textgreater log_{ frac{1}{5} }5\2-x textless 5\-x textless 3\x textgreater -3](https://tex.z-dn.net/?f=log_%7B+frac%7B1%7D%7B5%7D+%7D+%282-x%29+textgreater++-1%5Clog_%7B+frac%7B1%7D%7B5%7D+%7D+%282-x%29+textgreater++-1log_%7B+frac%7B1%7D%7B5%7D+%7Dfrac%7B1%7D%7B5%7D%5Clog_%7B+frac%7B1%7D%7B5%7D+%7D+%282-x%29+textgreater++log_%7B+frac%7B1%7D%7B5%7D+%7D5%5C2-x+textless++5%5C-x+textless++3%5Cx+textgreater++-3)
Ответ:![-3 textless x < 2 -3 textless x < 2](https://tex.z-dn.net/?f=-3++textless++x+%26lt%3B+2)
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