Question

(6x+3) в квадрате=(x-4)в квадрате

Answer 1

(6x + 3)^2 - (x - 4)^2 = 0
(6x + 3 - x + 4)(6x + 3 + x - 4) = 0
(5x + 7)(7x - 1) =0

5x + 7 = 0
5x = - 7
x = - 1,4

7x - 1 = 0
7x  = 1
x = 1/7