Question

Помогите решить
3(1-x)^4+(x-1)^2-4=0

Answer 1

(1-x)^4 = (x-1)^4 = ((x-1)^2)^2
Замена (x-1)^2 = y >= 0 при любом x
3y^2 + y - 4 = 0
(y - 1)(3y + 4) = 0
3y + 4 = 0; y = -4/3 < 0 - не подходит
y - 1 = 0; y = 1
(x - 1)^2 = 1
x - 1 = -1; x1 = 0
x - 1 = 1; x2 = 2