Question

Решить неравенства:

1) 9-((5x-2)/2))>x+5

2) 1,75+(2X/3)≤X+1(2/3)

Answer 1

============ 1 ============

$9-( \frac{5x-2}{2} )\ \textgreater \ x+5 | \cdot2\\ 18-( 5x-2)\ \textgreater \ 2x+10\\ 18-5x+2\ \textgreater \ 2x+10\\ -5x-2x\ \textgreater \ 10-20\\ -7x\ \textgreater \ -10\\ x\ \textless \ \frac{10}{7}\\ x\ \textless \ 1 \frac{3}{7}$

============ 2 ============

$1.75+ \frac{2x}{3} \leq x+1 \frac{2}{3} \\ 1 \frac{75}{100} + \frac{2x}{3} \leq x+\frac{5}{3} \\ 1 \frac{3}{4} + \frac{2x}{3} \leq x+\frac{5}{3} \\ \frac{7}{4} + \frac{2x}{3} \leq x+\frac{5}{3} | \cdot12\\ 21+8x \leq 12x+20\\ 8x-12x \leq 20-21\\ -4x \leq -1\\ 4x \geq 1\\ x \geq \frac{1}{4}$