Question

3а/а-3 + а+5/6-2а * 54/5а+а²

Answer 1

Ответ:

$\tt\displaystyle \bold{\frac{3a+9}{a} }$

Объяснение:

$\tt\displaystyle \frac{3a}{a-3}+\frac{a+5}{6-2a}*\frac{54}{5a+a^2}=\frac{3a+9}{a}\\\\\\\\1)\ \frac{a+5}{6-2a}*\frac{54}{5a+a^2}=\frac{a+5}{2(3-a)}*\frac{2*27}{a(5+a)}=\frac{27}{a(3-a)}\\\\\\2)\ \frac{3a}{a-3}+\frac{27}{a(3-a)}=\frac{3a}{a-3}-\frac{27}{a(a-3)}=\frac{3a^2-27}{a(a-3)}=\frac{3(a^2-9)}{a(a-3)} =\\\\\\=\frac{3(a-3)(a+3)}{a(a-3)}=\frac{3(a+3)}{a}=\frac{3a+9}{a}$