Question

решите тригонометрическое уравнение :

sin a*cos a / 0.5(1-2sin^2 a)=

Answer 1

$\displaystyle \frac{\sin \alpha \cos \alpha }{0.5(1-2\sin^2\alpha)} = \frac{2\sin\alpha\cos\alpha}{1-2\sin^2\alpha} = \frac{\sin2\alpha}{\cos2\alpha} =tg2\alpha$

Answer 2

sina*cosa/0,5(1-2sin²a)=0,5sin2a/0,5cos2a=tg2a