Question

помощььььььььььььььььььььььььььььььь

Answer 1

$1)\,\,\, 3 \sqrt{5} = \sqrt{3^2\cdot 5} = \sqrt{45}\\ \\ 2)\,\, \sqrt{50}= \sqrt{25\cdot 2} = \sqrt{5^2\cdot 2}=5 \sqrt{2} \\ \\ 3)\,\,\displaystyle \sqrt{ \frac{72a^6b^7}{49y^8} }= \sqrt{ \frac{36\cdot 2\cdot (a^3)^2\cdot b^6\cdot b}{7^2\cdot (y^4)^2} } = \frac{6a^3|b|^3 \sqrt{2b} }{7y^4}$