Question

Решите пожалуйста, номера 4.7 и 3.18) Срочно!))

Answer 1

$frac{(-5)^6*(-5)^7*(-5)^8}{(-5)^{14}*(-5)^4}= frac{(-5)^{21}}{(-5)^{18}} =(-5)^{21-18}=(-5)^3=-125$

$frac{1,2^{40}*1,2^{25}*1,2^4}{1,2^{59}*1,2^8} =1,2^{40+25+4-59-8}=1,2^2=1,44$

$frac{ (frac{1}{3} )^{10}* (frac{1}{3} )^{20}* (frac{1}{3} )^{30}}{ (frac{1}{3} )^{34}* (frac{1}{3} )^{23}}= (frac{1}{3} )^{10+20+30-34-23}= (frac{1}{3} )^3= frac{1}{27}$

$frac{ (-frac{1}{6} )^{25}* (-frac{1}{6} )^{19}* (-frac{1}{6} )^{16}}{ (-frac{1}{6} )^{8}* (-frac{1}{6} )^{49}}= (-frac{1}{3} )^{25+19+16-8-49}= (-frac{1}{6} )^3= -frac{1}{216}$

(5²)²-600=5⁴-600=625-600=0
(3³)²-271=3⁶-271=729-271=458
1000-5*(2³)²=1000-5*2⁶=1000-5*2*2⁵)=1000-10*32=10(100-32)=10*68=680
$( (frac{1}{2})^4)^2*320=2^{-8}*32*10=2^{-8}*2^5*2*5=2{-2}*5= frac{5}{4} =1,25$
(2⁴)²-200=2⁸-200=256-200=56
$(( frac{2}{3})^2)^3 * frac{3645}{32} =frac{2^6}{3^6} * frac{5*729}{2^5} =frac{2}{3^6} * 5*3^6 =10$