Question

решите систему неравенств.

Answer 1

$left { {{x^2-3x-4 textless 0} atop {3x-12 textgreater 0}} right. \ x^2+x-4x-4 textless 0 \ x(x+1)-4(x+1) textless 0 \ (x-4)(x+1) textless 0$
ОДЗ
$left { {{x-4 textless 0} atop {x+1 textgreater 0}} right. \ left { {{x-4 textgreater 0} atop {x+1 textless )}} right. \ left { {{x textless 4} atop {x textgreater -1}} right. \ left { {{x textgreater 4} atop {x textless -1}} right.$
x∈(-1;4)
x∈∅
x∈(-1;4)