Question

1) Lim x->3 x^2-5x+6/x^2-9

2) Lim x->oo 1-2x^2/x^2+4x

3) Lim x->oo 1-√1-x^2/x^2

Answer 1

$lim_{x to3} frac{x^2-5x+6}{x^2-9} =[ frac{0}{0} ]= lim_{x to3} frac{(x-2)(x-3)}{(x+3)(x-3)} = lim_{x to3} frac{x-2}{x+3}= frac{3-2}{3+3} = frac{1}{6}\ lim_{x to infty} frac{1-2x^2}{x^2+4x} = lim_{x to infty} frac{x^2( frac{1}{x^2} -2)}{x^2(1+ frac{4}{x}) } = lim_{x to infty} frac{-2+ frac{1}{x^2} }{1+ frac{4}{x}} = frac{-2+0}{1+0} =-2$

третье непонятно, если уточните условие, то добавлю

Answer 2

Под корнем?