Question

очень срочно надо помогите решить уравнение (t+4)²-(t-6)²=40

Answer 1

$(t+4)^2-(t-6)^2=40$
$t^2+8t+16-(t^2-12t+36)=40$
$t^2+8t+16-t^2+12t-36=40$
$20t-20=40$
$t-1=2$
$t=2+1$
$t=3$

Answer 2

$(t+4)^2-(t-6)^2=40$
$t^2+8t+16-(t^2-12t+36)=40$
$t^2+8t+16-t^2+12t-36=40$
$20t-20=40$
$t-1=2$
$t=2+1$
$t=3$

Answer 3

$(t+4)^2-(t-6)^2=40$
$t^2+8t+16-(t^2-12t+36)=40$
$t^2+8t+16-t^2+12t-36=40$
$20t-20=40$
$t-1=2$
$t=2+1$
$t=3$