Question

(2A-3)^2-(4A+1)*(A-7)

Answer 1

$(2A-3)^2-(4A+1)*(A-7)=4A^2-12A+9-(4A^2-28A+A-7)=\\4A^2-12A+9-4A^2+27A+7=15A+16$

Answer 2

= 2а^2 - 12а + 9 - 4a^2 + 28a - a + 7 = -2a^2 + 16a - a +16