Question

2^log2 7+2 log5 15-log5 9

Answer 1

$2^{log _{2} 7} +2log _{5} 15-log _{5}9 = 7+2log_{5} 15-log _{5} 9=7+log _{5} (15)^2-log _{5}=[tex]7+log x_{5} ( frac{15^2}{3^2} ) =7+log _{5} ( frac{15}{3} )=7+2log _{5} 5=7+2=9$