Question

3 и 6, помогите пожалуйста решить))))

Answer 1

3
1/cos²x -1=-tg²x
1+tg²x-1=-tg²x
tg²x+tg²x=0
2tg²x=0
tg²x=0
tgx=0
x=πk,k∈z
2
f(x)=2sinπ/4cos(x-π/6)
f(x)=2*√2/2cos(x-π/6)
f(x)=√2cos(x-π/6)
√2cos(x-π/6)=-1
cos(x-π/6)=-1/√2
x-π/6=-3π/4+2πk,k∈z U x-π/6=3π/4+2πk,k∈z
x=π/6-3π/4+2πk,k∈z U x=π/6+3π/4+2πk,k∈z
x=-7π/12+2πk,k∈z U x=11π/12+2πk,k∈z