Question

$3sqrt{x} + 2 sqrt{x} -12=0$

Answer 1

$3sqrt{x} + 6sqrt{x} -12=0 \9sqrt{x}=12 \sqrt{x}= frac{12}{9} \x=(frac{4}{3} )^2= frac{16}{9}$
Ответ: $x=frac{16}{9}$

Answer 2

$3 sqrt{x} +2 sqrt{x} -12=0$
замена
$sqrt{x} =a \ \ 3a+2a-12=0 \ 5a=12 \ a= frac{12}{5} \ \ sqrt{x} = frac{12}{5} \ \ x= frac{144}{25}$

Answer 3

вместо 2 ки 6?