Question

Решите уравнение
$2x^{2}-4x+2=0$

Answer 1

2x^2 - 4x + 2 = 0
2( x^2 - 2x + 1 ) = 0
2( x - 1 )^2 = 0 
x - 1 = 0
x = 1

Answer 2

Решение:
$2x^{2}-4x+2=0\\x^{2}-2x+1=0\\D_1 =k^{2}-ac=1-1=0\\x=\frac{-k + \sqrt{D_1}}{a}\\x=1$
Ответ: 1
____________________
$k=\frac{1}{2}b$