Question

Срочно логарифмы .........

Answer 1

$1)$

$frac{5^{log_52}+10^{1-lg2}}{2^{log_25}} = frac{2+ frac{10}{10^{lg2}} }{5}}= frac{2+ frac{10}{2} }{5} = frac{7}{5}=1.4$

$2)$

$36^{log_65}+10^{1+lg2}-3^{log_936}=6^{2{log_65}}+10^{1}*10^{lg2}-3^{log_{3^2}6^2}=$$=6^{{log_65^2}}+10*2-3^{2* frac{1}{2} log_{3}6}=6^{{log_625}}+10*2-3^{ log_{3}6}=25+20-6=39$

P. S.

$a^{log_ab}=b$

Answer 2

a^log(a)b=b       
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(5^log(5)2+10:10^lg2)/2log(2)5=(2+10:2)/5=(2+5)/5=7/5=1,4

(6²)^log(6)5+10*10^lg2-3^log(3²)6²=6^log(6)25+10*2-3^log(3)6=
=25+20-6=39