Question

разложить вектор С=(8 , 9) по векторам A=(2 , -3) и B=(1 , 2)

Answer 1

$left { {{2k+m=8} atop {-3k+2m=9}} right. <=> left { {{m=8-2k} atop {-3k+2(8-2k)=9}} right. <=> left { {{m=8-2k} atop {-3k+16-4k=9}} right. <=>\ \ <=> left { {{m=8-2k} atop {-7k=-7}} right.<=> left {{{m=8-2k} atop {k=1}} right.<=> left { {{m=8-2*1} atop {k=1}} right.<=> left { {{m=6} atop {k=1}} right.$
c=a+6b