Question

Помогите решить пожалуйста с подробным описанием

Answer 1

$sqrt{5-2sqrt{6}}=sqrt{(sqrt{3}-sqrt{2})^2}=|sqrt{3}-sqrt{2}|=sqrt{3}-sqrt{2};$

$5+2sqrt{6}=(sqrt{3}+sqrt{2})^2;$

$scriptstyle -49+20sqrt{6}=-(5^2-2cdot 5cdot (2sqrt{6})+(2sqrt{6})^2)= -(5-2sqrt{6})^2=-(sqrt{3}-sqrt{2})^4;$

$sqrt{27}-3sqrt{18}+3sqrt{12}-sqrt{8} =3sqrt{3}-9sqrt{2}+6sqrt{3}-2sqrt{2}= 9sqrt{3}-11sqrt{2};$

$a=-frac{(sqrt{3}-sqrt{2})(sqrt{3}+sqrt{2})^2(sqrt{3}-sqrt{2})^4}{9sqrt{3}-11sqrt{2}}= -frac{(sqrt{3}-sqrt{2})^3((sqrt{3})^2-(sqrt{2})^2)^2}{(sqrt{3}-sqrt{2})^3}=-1$

Ответ: 1 (истинны высказывания б, в, г)