Question

(x-2)^2-2(x+1)^2=(3-x)(3+x)

Answer 1

$(x-2)^2-2(x+1)^2=(3-x)(3+x) \ x^2-4x+4-2(x^2+2x+1)=9-x^2 \ x^2-4x+4-2x^2-4x-2=9-x^2 \ x^2-4x-2x^2-4x+x^2=9-4+2 \ -8x=7 \ x=- frac{7}{8}$